python Client.service 调用接口,老是出现下面错误 timeout

python Client.service 调用接口,老是出现下面错误 timeout

琴流音 发布于 2021-11-26 字数 1961 浏览 752 回复 1

Traceback (most recent call last):

  File "D:Python27libsite-packagesgeventgreenlet.py", line 327, in run

    result = self._run(*self.args, **self.kwargs)

  File "E:workcache.py", line 110, in inner_func2

    result=func(*args,**kwargs)

  File "E:workjinri_handler.py", line 110, in do_handle

    r=__client.service.GetRateListByPNR(s)

  File "buildbdist.win32eggsudsclient.py", line 542, in __call__

    return client.invoke(args, kwargs)

  File "buildbdist.win32eggsudsclient.py", line 602, in invoke

    result = self.send(soapenv)

  File "buildbdist.win32eggsudsclient.py", line 637, in send

    reply = transport.send(request)

  File "buildbdist.win32eggsudstransporthttps.py", line 64, in send

    return  HttpTransport.send(self, request)

  File "buildbdist.win32eggsudstransporthttp.py", line 77, in send

    fp = self.u2open(u2request)

  File "buildbdist.win32eggsudstransporthttp.py", line 118, in u2open

    return url.open(u2request, timeout=tm)

  File "D:Python27liburllib2.py", line 394, in open

    response = self._open(req, data)

  File "D:Python27liburllib2.py", line 412, in _open

    '_open', req)

  File "D:Python27liburllib2.py", line 372, in _call_chain

    result = func(*args)

  File "D:Python27liburllib2.py", line 1199, in http_open

    return self.do_open(httplib.HTTPConnection, req)

  File "D:Python27liburllib2.py", line 1174, in do_open

    raise URLError(err)

URLError: <urlopen error timed out>

<Greenlet at 0x20f6580: inner_func2('jinri', {'rt': u'1.u9ec4u666fu707f JQQQF1rn 2.  CZ629)> failed with URLError

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背叛残局 2021-11-26 1 楼

接口问题,返回数据过慢,造成 timeout