小问题有大难度 高手们都来看看！！

Question

下面是我自己做的一个类似收银的程序，可是在最后”remove“按键的时候，可以删除选择的东西，但是在total里面价钱没有删掉，怎么可以做到按了remove按钮，价钱也会同时删除呢？

import Tkinter

from Tkinter import *

import MySQLdb


window = Tkinter.Tk()


window.title("ETrolley")


window.geometry("500x360")


window.configure(bg="#cdc9c9")


title3=Label(window,text="",bg="#cdc9c9")


title1 = Label(window, text="------WELCOME TO ETrolley CHECKOUT------", bg="#cdc9c9")


title2 = Label(window, text="--Please scan your items--", bg="#cdc9c9")


barcodetitle = Label(window, text="---barcode---", bg="#cdc9c9")


itemtitle = Label(window, text="    Item_id    |    Item    |     Description     |    Price    ", bg="#cdc9c9")


barcode = Entry(window)


item = Text(window, height=4, width=35)


total = Text(window, height=1, width=5)


t1= Label (window,text="TOTAL", bg="#cdc9c9")


c1=Button(window,text="CHECKOUT",bg="#93ff00")


scroll = Scrollbar(window,orient=VERTICAL, bg="#93ff00")


scroll.config (command=item.yview)


item = Listbox(window,yscrollcommand=scroll.set,width=55,height=30,selectmode=EXTENDED)


title4=Label(window,text="",bg="#cdc9c9")


def one():

            user_input=barcode.get()        

            mycursor = db.cursor()

            mycursor.execute("""SELECT barcode, name, description,price FROM product

                         WHERE barcode = %s""", (user_input,))

            # calls fetchone until None is returned (no more rows)

            for row in iter(mycursor.fetchone, None):


                bar=row[0]


                name=row[1]


                des=row[2]


                pri=row[3]


               


                total.insert(END,row[3])

                item.insert(END,row)

                barcode.delete(0, 'end')  

def delete():

        item.delete(ACTIVE)

close = Button(window, text="remove",width=5, command=delete, bg="#ff4500")

go = Button(window, text="add!", command=one, bg="#93ff00")

title3.pack()

title1.pack()

title2.pack()

barcodetitle.pack()

barcode.pack(side=TOP);close.pack(side=RIGHT)

go.pack(side=TOP)

itemtitle.pack()

c1.pack(side=BOTTOM)

t1.pack(side=LEFT)

total.pack(side=LEFT)

scroll.pack(side=RIGHT,expand=1,fill=Y)

item.pack(side=LEFT,expand=0,fill= Y)

title4.pack()

#t1.pack()

window.mainloop()

Answer 1

这样看py代码好虐的感觉

Answer 2

def delete()

     itemText = #000000;">item.get(000000;">ACTIVE)
#000000;">000000;">

     item.delete(ACTIVE)

     解析价格，

#000000;">此外你000000;">totle的计算还存在问题

totleValueText = total.get(1.0,END)

totleValue = 0

if totleValueText !='n':

totleValue = int(totleValueText)

for row in iter(mycursor.fetchone, None):

     bar=row[0]

     name=row[1]

     des=row[2]

     pri=row[3]

      totleValue = totleValue + pri

      total.delete(1.0,END);

      total.insert(END,totleValue)

      item.insert(END,row)

#000000;">000000;">#000000;">000000;">

Answer 3

我不是高手，我是大神

Answer 4

难度太大，我做不了